20. A basketball star covers 2.80 m horizontally in a jump to dunk the ball (Fig. P4.20a). His motion through space can be modeled precisely as that of a particle at his center of mass, which we will define in Chapter 9. His center of mass is at elevation 1.02 m when he leaves the floor. It reaches a maximum height of 1.85 m above the floor and is at elevation 0.900 m when he touches down again. Determine (a) his time of flight (his “hang time”), (b) his horizontal and ....

 20. A basketball star covers 2.80 m horizontally in a jump to dunk the ball (Fig. P4.20a). His motion through space can be modeled precisely as that of a particle at his center of mass, which we will define in Chapter 9. His center of mass is at elevation 1.02 m when he leaves the floor. It reaches a maximum height of 1.85 m above the floor and is at elevation 0.900 m when he touches down again. Determine (a) his time of flight (his “hang time”), (b) his horizontal and (c) vertical velocity components at the instant of takeoff, and (d) his takeoff angle. (e) For comparison, determine the hang time of a whitetail deer making a jump (Fig. P4.20b) with center-of-mass elevations yi =1.20 m, ymax =2.50 m, and yf =0.700 m.








Publicar un comentario

Alguna duda?
Déjalo en los comentarios

Artículo Anterior Artículo Siguiente
Solución no disponible o no se encuentra tu ejercicio en nuestra página? Compra la solución del problema paso a paso desde 2.5 USD (dólares), 8.000 pesos colombianos o el equivalente en su moneda. Solicítalo preferiblemente por WhatsApp : +526567712411 o al correo fismatutor@gmail.com 


Nota: El servicio de resolución de ejercicios NO es gratuito.


Ofrecemos apoyo en tus exámenes, quizes o trabajos en física general, matemáticas, cálculo, entre otras áreas. Para mayor información entra en el siguiente Link



ESCRÍBANOS, NUESTRO TIEMPO DE RESPUESTA ES CASI INMEDIATA LAS 24/7

ULTIMOS COMENTARIOS